Question

. A candidate who gets 36% marks in an examination fails by 24 marks but another
candidate, who gets 43% marks, gets 18 more marks than the minimum pass marks.
Find the maximum marks and the percentage of pass marks.
write in detail...
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Answer 1

Answer:

Maximum marks 600

Pass mark 240 (40℅)

Step-by-step explanation:

Let the Maximum marks be x

And the pass marks be y

Given

$\frac{36x}{100} + 24 = y$

$\frac{43x}{100} - 18 = y$

Substraction of above two equations we get

$\frac{x}{100} (36 - 43) + 24 + 18 = 0$

$\frac{x}{100} ( - 7) + 42 = 0$

$x = ( - 42) \times \frac{100}{ - 7}$

$x = 600$

Also

$\frac{36 \times 600}{100} + 24 = y$

$y = 240$