Question

A CANDIDATE WHO GETS 36% MARKS IN AN EXAMINATION FAILS BY 24 MARKS BUT ANOTHER CANDIDATE, WHO GETS 43% MARKS GETS 18 MORE THAN PASSING MARKS THAN THE MINIMUM PASS MARKS. FIND THE MAXIMUM MARKS AND THE PERCENTAGE OF THE PASS MARKS​

Answer 1

Answer:

Let the Passing marks be x

and the Total marks be y

First Canditate=36% ofy+24=x

Second Canditate=43% ofy−18=x

First cand.=Second Cand.

100

36y

+24=

100

43y

−18

25

9y

+24=

100

43y

−18

24+18=

100

43y

−

100

36y

42=

100

7y

7

4200

=y=600

Total marks=600

100

36

y+24=x

10

36

×600+24=x

216+24=x

240=x

Passing marks=240