Question

A candidate who gets 36% marks in an examination fails by 24 marks but another candidate who gets 43% marks gets 18 more marks than the minimum pass marks find the maximum marks and the percentage of pass marks

Answer 1

please mark it as the brainliest answer

Answer 2

First candidate = 36% × x + 24
Second candidate = 43% × x - 18
First candidate = Second candidate
36/100 × x + 24 = 43/100 × x - 18
9x/25 + 24 = 43x/100 - 18
9x/25 - 43x/100 = -24 - 18
36x/100 - 43x/100 = -42
36x - 43x/100 = -42
-7x/100 = -42
x = -42 × -100/7
x = 600
Maximum marks = 600
36% × x + 24 = y
36/100 × 600 + 24 = y
216 + 24 = y
240 = y
Passing marks = 240