Question

A candidate who gets 36% marks in the examination fails by 24 marks but

another candidate, who gets 43% marks, gets 18 more marks than the

minimum pass marks. Find the maximum marks and the percentage of pass

marks.​

Answer 1

Answer:

First candidate = 36% × x + 24

Second candidate = 43% × x - 18

First candidate = Second candidate

36/100 × x + 24 = 43/100 × x - 18

9x/25 + 24 = 43x/100 - 18

9x/25 - 43x/100 = -24 - 18

36x/100 - 43x/100 = -42

36x - 43x/100 = -42

-7x/100 = -42

x = -42 × -100/7

x = 600

Maximum marks = 600

36% × x + 24 = y

36/100 × 600 + 24 = y

216 + 24 = y

240 = y

Passing marks = 240