a candidate who scored 30% failed by 5 marks by the candidate who scored 40% pass by 10 of minimum marks. what are the percent of minimum marks required to pass
And is 50
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let X be the passing marks and y be the total marks
ATQ : x-5 = 30% y equation 1
x+10 = 40% y equation 2
solving both equation by eliminating method, we get y = 150
putting the value of y in 1st equation
x = 30% × 150 + 5
= 45 + 5
= 50
ATQ : x-5 = 30% y equation 1
x+10 = 40% y equation 2
solving both equation by eliminating method, we get y = 150
putting the value of y in 1st equation
x = 30% × 150 + 5
= 45 + 5
= 50
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