A candle 3.0 cm high is placed 30 cm from a converging mirror with a focal length of 20 cm
Using the mirror and magnification equations, determine the image position and its height From
these results
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Explanation:
According to the problem,
As we have mirrors formula;1/f=1/v+1/u in which terms have their usual meaning.
Here,they gave..f=20(-ve) u=30(-ve),v=?
(Sign convention as it is concave mirror)
Substitute the values in above formula,
1/-20=1/-30+1/v
1/v=1/30–1/20
v=20*30/20–30
v=-60cm.(image length)
Now magnification for a mirror is ratio of image length and object length with (-ve) sign,
m=-v/u
m=-(-60)/(-30) =-2
Hence,image is magnified 2 times,real image and inverted.
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