A candle is 49 cm in front of a convex spherical
mirror, of radius of curvature 70 cm. (a) Where is
the image? (b) What is the magnification?
ans 0.204,0.417 erect
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Answered by
6
Answer:
a) Image formed (v)=20cm
b)magnification(m)= 0.40
Explanation:
To Find: Position at which Image is formed
Magnification
Given: Radius of Curvature=70cm
u=-49cm ( object is placed to the left side of the mirror)
Solution: f= 70/2 =35cm
1/f=1/u+1/v
1/35=1/v+1/(-49)
1/v=1/35+1/49
Thus,
v=20cm
For magnification,
m=-v/u
m=-20/-49
m=0.40
Thus, the image formed by the mirror is virtual, erect, and diminished.
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Answer:
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