Question

A candle is 49 cm in front of a convex spherical
mirror, of radius of curvature 70 cm. (a) Where is
the image? (b) What is the magnification?
ans 0.204,0.417 erect ​

Answer 1

Answer:

a) Image formed (v)=20cm

b)magnification(m)= 0.40

Explanation:

To Find: Position at which Image is formed

                  Magnification

Given: Radius of Curvature=70cm

             u=-49cm ( object is placed to the  left side of the  mirror)

Solution: f= 70/2 =35cm

 1/f=1/u+1/v

1/35=1/v+1/(-49)

1/v=1/35+1/49

Thus,

v=20cm

For magnification,

m=-v/u

m=-20/-49

m=0.40

Thus, the image formed by the mirror is virtual, erect, and diminished.

       

         

Answer 2

Answer:

follow

Explanation: