A candle is held 3cm away from a concave mirror radius of curvature is 24cm ?Where is image formed ? What is the nature of the image ?
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a) Using the relation, 1u+1v=1f
1
u
+
1
v
=
1
f
1v=1f−1u=1−18=1(−27)
1
v
=
1
f
-
1
u
=
1
-
18
=
1
(
-
27
)
v=-54cm
The negative sign shows that the image is formed in front of the mirror, i.e., on the side of the object itself. Thus, the screen must be placed in a distance of 54 cm in front of the mirror.
(b) Magnification,m=−vu=IO
-
v
u
=
I
O
we get, I2.5=−(−54)(−27)
I
2.5
=
-
(
-
54
)
(
-
27
)
or I=(2.5)×(−02)=−5cm
I
=
(
2.5
)
×
(
-
02
)
=
-
5
c
m
Thus clearly the image is real, inverted and magnified.
a) Using the relation, 1u+1v=1f
1
u
+
1
v
=
1
f
1v=1f−1u=1−18=1(−27)
1
v
=
1
f
-
1
u
=
1
-
18
=
1
(
-
27
)
v=-54cm
The negative sign shows that the image is formed in front of the mirror, i.e., on the side of the object itself. Thus, the screen must be placed in a distance of 54 cm in front of the mirror.
(b) Magnification,m=−vu=IO
-
v
u
=
I
O
we get, I2.5=−(−54)(−27)
I
2.5
=
-
(
-
54
)
(
-
27
)
or I=(2.5)×(−02)=−5cm
I
=
(
2.5
)
×
(
-
02
)
=
-
5
c
m
Thus clearly the image is real, inverted and magnified.
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