Question

A candle is kept at a distance equal to double the focal length form the pole of a convex mirror.
Its magnification will be​

Answer 1

Answer:

Magnification = 1

Explanation:

As it is given that a candle is kept at a distance equal to double the focal length form the pole of a convex mirror.

That is candle is placed at distance of 2f from pole of a convex mirror.

We know,

2f = c

So,

Object is placed at center of curvature distance which indicates, Image size will be same as object.

Therefore,

Size of image = Size of object = u

As we know that

$Magnification = \frac{size\ of\ image}{size\ of\ object}$

Therefore,

$Magnification = \frac{u}{u}$

∴ Magnification = 1

Answer 2

Answer:

Answer should be -1/3

Explanation:

1/v + 1/u = 1/f

⇒ 1/v + (-1/2f) = 1/f

⇒ 1/v = 3/2f

⇒ v = 2f/3

Now magnification = -v/u  (for mirror)

⇒ m = - (2f/3) /2f

⇒ m = -1/3

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