Math, asked by kiranharsh65, 2 months ago

A cane do alone
a plece of work in 24h
B can do alone a plece of work in 16h
But A, B, C both do a same work in 8 h
How many hours C alone Can finish
the work.​

Answers

Answered by harianand74
0

Answer:

48 hrs

Step-by-step explanation:

LCM 48

A = 2 units

B = 3 units

A+B+C = 6 units

(A+B+C) - (A +B) = 6 - 5 = 1

48/1 = 48hrs

Answered by prasanthikuchipudi
0

Answer:

48 days

Step-by-step explanation:

Given,

A cane do alone  a plece of work in 24h

A=1/24 h

B can do alone a plece of work in 16h

B=1/16 h

But A, B, C both do a same work in 8 h

A+B+C=1/8 h

from the above Equation

C=1/8-A-B

C=1/8-1/24-1/16

C=6-2-3/48

C=1/48

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