Math, asked by jboi2030, 1 year ago

A cane is being packed in a box.The box measures 20 inches by 12 inches by 6 inches . What is the longest canto the nearest inch ,that will fit in the box

Answers

Answered by isyllus
3

Answer:

The longest length of cane is 24 inches that fit in the box.

Step-by-step explanation:

A cane is being packed in a box.

The box measures 20 inches by 12 inches by 6 inches

We need to find longest cane fit in the box.

Box is cuboid shape. Longest length is body diagonal of box.

Dimension of box: Length (L) , Width (W) and Height (H).

\text{Length of longest Diagonal}=\sqrt{L^2+W^2+H^2}

Where, L=20 inches, W=12 in and H=6 in

\text{Longest Length of cane}=\sqrt{L^2+W^2+H^2}

\text{Longest Length of cane}=\sqrt{20^2+12^2+6^2}\approx 24

Hence, The longest length of cane is 24 inches.

Answered by amitnrw
3

Answer:

A cane is being packed in a box.The box measures 20 inches by 12 inches by 6 inches then longest canto the nearest inch ,that will fit in the box is 24 inch

Step-by-step explanation:

A cane is being packed in a box.The box measures 20 inches by 12 inches by 6 inches

Longest can which can be fitted is diagonally

do diagonal ² = 20² + 12² + 6²

=> diagonal ² = 400 + 144 + 36

=> diagonal ² = 580

=> diagonal = 24.08 ≈ 24 inch

24 inch longest can be fitted in box

Similar questions