A canister containing air has a volume of 85 cm3 and a pressure of 1.45 atm when the temperature is 310 K. What is the pressure when the volume is increased to 180 cm3 and the temperature is reduced to 280 K?
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Answer:
The pressure of the gas at 180cm³ volume and 280 k temperature is 0.58208 atm
Explanation:
Step 1 : Write down the formula relating temperature, volume and pressure.
The formula is given by :
(P1V1)/T1 = (P2V2)/T2
Where :
V = the volume of the gas.
T = Temperature of the gas.
P = Pressure of the gas.
Step 2 : Identify the given details from the question.
V1 = 85 cm³
P1 = 1.45 atm
T1 = 310 K
V2 = 180 cm³
T2 = 280 K
P2 =?.
Step 3 : Substitute the values in the formula.
(80 × 1.45)/310 = (180 × P2)/280
116/310 = 180P/280
280 × 116 = 180P × 310
32480 = 55800P2
P2 = 32840/55800
P2 = 0.58208 atm
Step 4 : The answer.
The pressure of the gas at 180cm³ volume and 280 k temperature is 0.58208 atm
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