Question

a canister has a small hole at its bottom water penetrates into the canister when it's base is at a depth of 40 cm from the surface of water. if surface tension of water is 73.5 dyne per cm find the radius of the hole.
NO STUPI D ANSWER.PLZ!​

Answer 1

1 dyne = 10^-5 N

so, 73.5 dyne = 0.000735 N

depth = 40cm = 0.4 m

radius of hole = 0 .000735 / 0.4 = 0.00018375

Answer 2

Answer:

Water Drop

P = 2T/R

P = p g H

P = 4 × 10^3

T = 73.5 × 10^2 × 10^-5

R = 37.5× 10^-6

R = .0375 mm