A cannal of width 1m is construded all along in side the field which is 24m long and 18m wide find the area of the cannal the cost of construction of a cannal of the rate of 12per sq.m
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Question 3.
A circular carpet whose radius is 106 cm is laid on a circular hall of radius 120 cm. Find the area of the hall uncovered by the carpet.
Solution:
Radius of the circular hall R = 120 cm
Radius of the circular carpet r = 106 cm
Area of the hall uncovered = Area of the hall – Area of the carpet
= π (R2 – r2) cm2
= 227 × (1202 – 1062) cm2
= 227 × (120 + 106) × (120 – 106) cm2
= 227 × 226 × 14 cm2 = 9,944 cm2
Area of the hall uncovered = 9, 944 cm2
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Radius of the circular hall R = 120 cm
Radius of the circular carpet r = 106 cm
Area of the hall uncovered = Area of the hall - Area of the carpet
= T (R2 – r2) cm2
= 227 x (1202 – 1062) cm2
= 227 x (120 + 106) x (120 – 106) cm2
= 227 x 226 × 14 cm2 = 9,944 cm2
Area of the hall uncovered = 9, 944 cm2
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