Question

A cannon ball is fired with a velocity 200 m/s at an angle of 60 degree with the horizontal. At the highest point of its flight it explodes into 3 equal fragments ,one going vertically upwards with a velocity 100m/s.The third fragment will moving with a velocity

Answer 1

Answer:

300 m/s

Step by step explanation:

Let the mass of the cannon ball be 'M'. Therefore, each fragment has a mass of M/3 (equal masses).

The vertical component of the velocity = v*cos(60)= 200*0.5 = 100 m/s.

The horizontal component of velocity = v*sin(60)= $100\sqrt{3}$ m/s.

At the highest point, the velocity will be horizontal only because of the gravitational force.

Now, apply the conservation of momentum law, the momentum in the horizontal direction before explosion = momentum in the horizontal direction after explosion.

Hence,

$100*M=\frac{M}{3}*v_3$; where $v_3$ is the velocity of the third fragment.

Therefore, $v_3=300\:m/s$.