Question

A cannon fires a shell with a speed of 84 M per second when they cannon is inclined at 45 degree horizontal distance covering in observed 630m what percent of decreasing the horizontal distance observed due to air resistance

Answer 1

$range = {u}^{2} \sin(2 \alpha ) \div g \\ = \frac{ {84}^{2} \times \sin(90) }{9.8} \\ = 720 \: m$
decreased dist = 720 - 630 = 90 m
% decreased = 90 x 100 / 720 = 12.5 %