Question

A cannon is fired with a muzzle velocity of 150m/s at an angle of
elevation equal to 45 degrees
.

i) What is the maximum height the ball reaches?
ii) What is the total time aloft?
iii) How far did the ball land?
iv) What is the distance and height of the projectile 10 seconds after
firing?

Answer 1

Answer:

At the balancing condition, Anticlock wise moment must be equal to clock wise moment.

Clockwise moment, about the balancing point is

= moment by 80 gf

=80gf×(80−X)cm

=6400gfcm−80Xgfcm.....(1)

Anticlock wise moment about the balancing point is

= moment by 10 gf + moment by 50 gf

=10gf×(X−10)+50gf×(X−50)

=10Xgfc,−100gfcm+50Xgfcm−2500gfcm.....(2)

At the balancing condition, Clock wise at equilibrium = Anti clock wise moments.

6400−80X=100X−100+50X−2500

6400+2600=140X⇒140X=8000

⇒X=1408000=64.28

Scale is balanced at 64.28 cm from the beginning