Question

A cannon of mass 1000 kg launches a cannonball of mass 10 kg at a velocity of 100 m/s. At what speed will the cannon recoil?​

Answer 1

Answer:

-1 m/s

Explanation:

As per the law of conservation of momentum,

m₁v₁ = m₂v₂

Given :

m₁ = 10 kg

v₁ = 100 m/s

m₂ = 1000 kg

v₂ = ?

Procedure :

m₁v₁ = m₂v₂

⇒ (10)(100) = (1000)(v₂)

[Let v₂ = v for simplicity]

⇒ 1000 = (1000)(v)

∴ v = 1 m/s in the opposite direction of the cannonballs'.

∴ v = -1 m/s

Thanks !