Question

A cannon of mass 12000 kgs on smooth platform fires a shell of mass 300 kg in horizontally direction with a velocity 400 metres per second find the velocity of the c a n n o n after it is s h o t​

Answer 1

Answer:

There is no external force to the system. Therefore we can use linear momentum conservation theorem.

momentum of the system before collision =momentum of the system before collision

m1V= m2V2 + m1V1 ------ (1)

Where, m1 = mass of the cannon = 12000 kg

           V = initial velocity of the cannon = 0

           m2 = mass of shell = 300 kg

           V2 = velocity of shell = 400 m/s

           V1 = final velocity of cannon

Substituting above value for equation (1),

   12000*0 = 300*400+12000*V1

  12000V1 = -22000

   V1 = -2m/s

Answer: velocity of the cannon = -2 m/s (----> direction)

           velocity of the cannon = 2 m/s (<---- direction)

Answer 2

Explanation:

hey army @danitha844

please inbox me .............