A cannon of mass m, = 10000kgs located on a smooth horizontal platform fires a shell of mass m2= 200kg in horizontal direction with a velocity V2 = 300m/s. Find the velocity of the cannon after it is shot.
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Answer:
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Given data : A cannon of mass (m) is 10000 kg located on a smooth horizontal platform fires a shell of mass (m') is 200kg in horizontal direction with a velocity (v') is 300 m/s.
To find : Find the velocity of the cannon after it is shot.
Solution : Here, according to given data,
- Mass of Cannon, m = 10000 kg = 10⁴ kg
- Mass of a Shell, m' = 200 kg
- Final velocity of Shell, v' = 300 m/s
Here, we know that,
- Initial velocity of Cannon, u = 0
- Initial velocity of Shell, u' = 0
- Final velocity of Cannon, v = ?
Now, by Newton's third law,
➜ Original momentum = Final momentum
➜ m * u + m' * u' = m * v + m' * v'
➜ (10⁴ * 0) + (200 * 0) = (10⁴ * v) + (200 * 300)
➜ 0 + 0 = v * 10⁴ + 6 * 10⁴ i.e.
➜ v * 10⁴ + 6 * 10⁴ = 0
➜ v * 10⁴ = - 6 * 10⁴
➜ v = (- 6 * 10⁴)/10⁴
➜ v = - 6 m/s
Where, negative sign indicates opposite direction.
∴ v = 6 m/s
So, Cannon move in an opposite direction.
Answer : Hence, the velocity of the cannon after it is shot is 6 m/s.