Question

A cannon shoots a 40 kg ball at a sailing ship and when it hits the wall of the vessel it applies 2000 N force how much was it decelerated

Answer 1

Explanation:

we know for=ma

by arrenging we got a=f/m

2000/40=50m/s answer is this

Answer 2

Answer:

The deceleration of the Cannon ball is 50m.sec^−2

Explanation:

Provided that:

Mass of the Cannon ball (m) = 40 kg

Force applied by the Cannon ball on vessel (F) = 2000 N

From Newton's laws of motion, we know;

$F = m.a \: \: ...(Newton's\: 2nd \: law)$

Where m = mass and ;

a = acceleration or deceleration

So we get;

$a = \frac{F}{m} \: m. {sec}^{ - 2} \\a = \frac{2000}{40} \: m.{sec}^{ - 2} \\ a = 50 \: m.{sec}^{ - 2}$

Hence, the deceleration of the Cannon ball is 50m.sec^−2.

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