asked by husainaltaph3, 14 days ago

# A canoe has a velocity of 0.4m/s southeast related to the earth the canoe is on the river which is flowing with a velocity of 0.5m/s relative to the earth . find the magnitude and direction of the velocity of the canoe with respect to the river.​

5

PLS MARK ME BRAINLIEST

Explanation:

The addition of the two vectors   boat from river + river from earth = boat from earth. So to get boat from river we must subtract.  boat from earth - river from earth. the river is 0.520 eastThe boat from earth is 0.420 * sin (45)  east = 0.297 east

and 0.420 * cos ( 45) south = 0.297 south  The boat from earth is 0.420 * sin (45)  east = 0.297 east

and 0.420 * cos ( 45) south = 0.297 south  The boat from earth is 0.420 * sin (45)  east = 0.297 east

and 0.420 * cos ( 45) south = 0.297 south  Subtract the velocity of the river from earth ( i.e add 0.520 west )  to get the result.  0.297 south remains but the other component is now 0.223 west.

Use pythagoras theory to calculate the magnitude.

0.371

For the angle west of south,

tan(x) = 0.223 / 0.297

x = atan(0.223/0.297)

= 36.9 degrees west of south

0

A canoe has a velocity of 0.40 m/s southeast relative to the earth. The canoe is on a river that is flowing 0.50 m/s east relative to the earth. Find the velocity (magnitude and direction) of the canoe relative to the river.

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