A cantilever beam, which is made of an alloy with Young’s modulus of elasticity E=72×(10)9N/m2, is loaded transversely at its free end. If the length of the beam is 750 mm and the beam has an annular cross-section with inner and outer diameters of 110 mm and 120 mm, respectively, then determine the equivalent stiffness (in N/m) of this beam.
1.531×(10)6
3.06×(10)6
2×(10)6
4×(10)6
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The equivalent stiffness of this beam is K = 3.06 x 10^6 N/m
Explanation:
- k = 3 EL / L^3 ----(i)
- The moment of inertia will b determined as;
- I = π / 32 [d^4 (outer) - d^4 (inner)]
I= π/32 [ (120 x 10^-3)^4 - (110 x 10^-3)^4]
I = 5.98 x 10^-6 m^4 ----(ii)
From equation (i)
K = 3 x (72 x 10^9) x (5.98 x 10^-6) / (750 x 10^3)^3
K = 3.06 x 10^6 N/m
Thus when the length is increased from 750 mm to 1500 mm then stiffness decreases from 3.06 x 10^6 N/m to 0.383 x 10^6 N/m.
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