A cantilever of 2m length carries a point load of 20 KN at 0.8 m from the fixed end and
another point of 5 KN at the free end. In addition, a u.d.l. of 15 KN/m is spread over the
entire length of the cantilever. Draw the S.F.D, and B.M.D
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Answer:
Support Reaction Calculation
ΣFy=0ΣFy=0
RA−4−(2x2)=0RA−4−(2x2)=0
RA=8kNRA=8kN
Shear Force Calculations:
(F)A=+8kN(F)A=+8kN
(FR)A=+8kN(FR)A=+8kN
(F)C=+8kN(F)C=+8kN
(F)B=+4=4kN(F)B=+4=4kN
(FR)B=4−4=0kN(FR)B=4−4=0kN
Bending Moment Calculations:
MB=0kN−mBisfreeend.MB=0kN−mBisfreeend.
MC=−(4x2)−(2x2)x1=−12kN−mMC=−(4x2)−(2x2)x1=−12kN−m
M
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