A capacitance of 12 microfarads is used in a defibrillating device to restore normal heart function. It is charged at 6kV and then discharged in 4 milliseconds, what will be the current flowing in the body?
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Answer:
18 A
Explanation:
Q = CV
Current = Q/t
Q = 6kV × 12 microF
Q = 72 × 10^(-3)
Current = 72× 10^(-3) / (4× 10^(-3))
= 18 A
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