Question

A capacitor consists of three parallel plates of equal area A. The distance between them is d1 and d2. Dielectric having pemittivity ε1 and ε2 is present between the plates. i) Calculate the capacitance of such a system. ii) Express this capacitance in terms of K1 and K2.

Answer 1

Answer:

Final Answer :

C(eq) = £° A (1 /( (d1/£1)+ (d2/£2))

EXPLANATION ..

Steps and Understanding :

1) Relative Permitivity/ Dielectric Constant :

£1,£2.

Capacitance of a two parallel plates separated by d1 distance, filled by dielectric of dielectric Constant £1 is

C (1) = £1£°A / (d1 ).

2) Similarly,

C(2) = £2£°A/(d2)

3) Given us system of two series plate,

so

\frac{1}{c(eq)} = \frac{1}{c(1)} + \frac{1}{c(2)}

c(eq)

1

=

c(1)

1

+

c(2)

1

=> 1/c(eq) = d1 / (£1£° A) + d2 / (£2£°A)

=> C(eq) = £° A ( 1/ (d1/£1) + 1/(d2/£2))

Answer 2

Answer:

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