A capacitor has a capacitance of 0.40 µF at a voltage of 9.0 V. What is the charge on each plate of the capacitor?
katelynhockeyp6vsjl:
ANSWER: 3.6
Answers
Answered by
6
q = CV
= 0.40* 10^-6 * 9
= 3.6 * 10^-6 coulomb
= 0.40* 10^-6 * 9
= 3.6 * 10^-6 coulomb
Similar questions
Chemistry,
8 months ago
English,
8 months ago
Math,
8 months ago
India Languages,
1 year ago
Biology,
1 year ago
Social Sciences,
1 year ago
Math,
1 year ago