A capacitor has capacitance 6 microfarad and 220v.How many such are required to produce capacitor of 12 microfarad and 440v.
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Answer:
Recall
1
C
eq
=
1
C
1
+
1
C
2
+
1
C
3
...
in series
C
eq
=
C
1
+
C
2
+
C
3
+
...
in parallel
To have 1000 V tolerance, you need to stack up four 8
μ
F
capacitor in series. The equivalent capacitance of 4 such capacitors is:
1
C
eq
=
1
8
μ
F
+
1
8
μ
F
+
1
8
μ
F
+
1
8
μ
F
=
1
2
μ
F
⇒
C
e
q
=
2
μ
F
To make a total of 16 muF that tolerates 1000V, you need 8 set of them arranged in parallel such that
2
μ
F
+
2
μ
F
+
2
μ
F
+
...
=
16
μ
F
⇒
total number of capacitors = 8 x 4 = 32
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