Question

A capacitor having capacitance C is charged to a voltage V. It is then removed and connected in parallel with another identical capacitor which is uncharged. The new charge on each capacitor is?​

Answer 1

Answer:

The new charge on each capacitor is cv /2

Explanation:

for explanation see the attached photo

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Answer 2

Answer:

The new charge on each capacitor is $\frac{Q}{2}$.

Explanation:

Case: I

The charge on the capacitor when it is connected to the battery of voltage V is,

$Q=CV$         (1)

Q=charge on the capacitor

C=capacitance of the capacitor

V=voltage of battery

Case: II

The capacitor is connected in parallel with another identical capacitor which is uncharged. And in the parallel combination, we know that the voltage remains the same. i.e.

$V_c=\frac{Q}{C_e_q_v}$               (2)

Vc=voltage across the combination of capacitors

Q=total charge

Ceqv=equivalent capacitance=2C         (∵ both the capacitors are connected in parallel)

Then equation (2) becomes,

$V=\frac{Q}{2C}$             (3)

The charges on the capacitors,

$Q_1=CV_c=C\frac{Q}{2C}=\frac{Q}{2}$

$Q_2=CV_c=C\frac{Q}{2C}=\frac{Q}{2}$

Hence, the new charge on each capacitor is $\frac{Q}{2}$.