Question

A capacitor holds 2.5×10^-3 Coulombs of charge when the potential difference is 950 Volts. What is the capacitance?

Answer 1

we know, Q= CV    {must remember equation}

so C= Q/V

C= 2.5×10^-3 / 950

= 2.63 x 10^-6 Farad

or 2.6 micro farad

or 2.6 μF

Here you go mate, tell me if you didn't understand it

Answer 2

Answer:

2.63×10^-6

Explanation:

Q= CV

C = Q/V

C = 2.5×10^-3/950

C = 2.63 × 10^-6