A capacitor is charged by 200v supply. The supply is then disconnected and the charged capacitor is connected to another uncharged 2 c capacitor. How much electrostatic energy of the first capacitor is lost in the process of attaining the steady situation?
Answers
Answered by
0
V=200V
Q=2C
Energy is capacity to do work
W=VQ
=200×2=400J
Similar questions