A capacitor is charged by
using a battery which is then
disconnected. A dielectric slab
is then slipped between the
plates which results in
Answers
Answered by
1
Answer:
A dielectric slab is then slipped between the plates, which results in. Solution : Battery in disconnected so Q will be constant as C∝K. So with introduction of dielectric slab capacitance will increase using Q=CV,V will decrease and using U=Q22C, energy will decrease.
Similar questions