A capacitor is connected across a battery & the plate separation of capacitor is increase without removing the battery then
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First of all, when plate separation is changed without disconnecting the battery then the potential difference across the capacitor plates will remain constant. Now, initial Capacitance be C : With increased value of 'd' , capacitance will decrease. ... Since Capacitance is decreasing, Charge will also decrease
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When a capacitor is connected across a battery and plate separation of capacitor increases without removing the battery, then the capacitance of the capacitor decreases.
- Since the capacitor of capacitance is inversely proportional to the distance between them, so when the distance increases, then the capacitance decreases.
- As the battery is not removed, then the charge remains constant.
- The charge remains constant. As, Q = CV ( Where Q is the charge, C is the capacitance of a capacitor, and V is the potential difference across the capacitor.) Therefore, the potential difference across the capacitor increases to compensate for the decline of capacitance.
- As the energy stored in the capacitor is inversely proportional to the potential difference provided charge remains constant. So the potential energy stored in the capacitor will decrease.
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