A capacitor is fully charged after 25 seconds to a battery voltage of 20 volts. The battery is replaced with a short circuit. What will be the voltage across the capacitor after one time constant?
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0
Explanation:25n*20g thn3. 8,*10 to the power of 9
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6
Answer:
7.36 V
Explanation:
1 Time Constant for Volt = 63.2%
63.2%*20 = 12.64V
Volt Across = 20V-12.64V
= 7.36
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