Question

A capacitor is made by two parallel plates with area of each being A and distances between them as d. This is placed in an electrolyte with resistivity ⍴ and constant horizontal velocity v. The entire system is placed in a uniform magnetic field of induction β at 30o angle from the plate. The material between the places has an external resistance of R.

Calculate the amount of power generated in that resistance?

Answer 1

Answer:

Answer

Correct option is

D

2wl

2

∈

0

Q

2

d

(K−1)

Let at any moment of time when slab traveled distance x,

Capacitance due to dielectric slab,

C

d

=Kϵ

o

A/d=Kϵ

o

(wx)/d

Capacitance where slab is not there:

C=ϵ

o

(w(l−x))/d

Net capacitance will be:

C

′

=

d

wϵ

o

(l+(k−1)x)

Now, energy U is:

U=

2C

′

Q

2

=

2wϵ

o

l

Q

2

d

(

1+

l

(K−1)x

1

)

Force, F=−dU/dx, therefore,

F=

2wϵ

o

l

2

Q

2

d

(K−1)

Explanation:

I hope this is helpful for you.

Answer 2

Answer:

445667.8866amount is your answer