Physics, asked by johnsali2002, 6 months ago

A Capacitor of 0.6 mew F is charged to 220V. Find the energy when fully charged.

Answers

Answered by prachikumari2802

0

Answer:

Charge will be 1.32×10 ^-4 C

Explanation:

q=CV

q= 0.6 ×10 ^-6×220

q= 1.32× 10^-4 C

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