Question

A capacitor of 10 and one of 206F are connected across batteries of 600 volts and 1000 volts respectively and They are then joined in parallels. What is the charge on each capacitor?​

Answer 1

Answer:

Charge on capacitor equals:

=

where is capacitance, is voltage on capacitor.

If capacitor is connected across battery:

1 = 11

2 = 22

If they are joined in parallel:

1

′ = 2

′

The law of conservation of charge:

1 + 2 = 1

′ + 2

′

Or:

{

1

′

1

=

2

′

2

1

′ + 2

′ = 11 + 22

Therefore:

1

′ =

11 + 22

1 +

2

1

= 8.7 ⋅ 10−6

2

′ =

11 + 22

1 +

1

2

= 1.7 ⋅ 10−5

Answer: 8.7 ⋅ 10−6

and 1.7 ⋅ 10−5