Question

A capacitor of 100 uf is charged to 10v through a resistance of 10kohm it would be fully charged in

Answer 1

Answer:The time constant is determined as

Formula

where τ is the time constant in seconds, R is the resistance in ohms and C is the capacitance in farads. The time constant of an RC circuit is defined as the time it takes for the capacitor to reach 63.2% of its maximum charge capacity provided that it has no initial charge. Note that the capacitor will be 63.2% charged after τ and almost fully charged (99.3%) after approximately 5τ.

Energy stored E in the capacitor when it is fully charged to voltage U (charging time T >> τ)

Formula

where C is the capacitance in farads and V is the voltage in volts.

Maximum current I is determined from Ohm’s law:

Formula

Maximum charge Q is determined as follows:

Formula

where C is the capacitance in farads and U — voltage in volts.

Explanation:

Answer 2

Answer:

The capacitor will be fully charged in 1 second.

Explanation:

The time required to charge a capacitor is calculated as,

$\tau=RC$          (1)

Where,

τ=time required to charge a capacitor

R=resistance of the resistor

C=capacitance of the capacitor

From the question we have,

C=100μF

R=10kΩ=10×10³Ω

By putting the values in equation (1) we get;

$\tau=10\times 10^3\times 100\times 10^-^6$

$\tau=1 \ second$

Hence, the capacitor will be fully charged in 1 second.

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