Question

a capacitor of 2 microfarad is charged to 200 v. it is now discharged through a resistance , the heat produced in resistance is ??

Answer 1

The heat produced means the energy is not dependent on the resistance so (U=1/2 cv^2) which is equals to U = 1/2 (200*10^-6)(200*200) = 4Joule. So in both case the heat produced will be 4 joule. Hope u r satisfied with this answer.....

Answer 2

Given that,

Capacitance, $C=2\ \mu F=2\times 10^{-6}\ F$

Potential difference, V = 200 V

Let the capacitor discharge separately through resistance of 2 ohms and 8 ohms,

To find,

The heat produced in resistance the resistance.

Solution,

The heat produced doesn't depends upon value of resistance. For a capacitor, heat produced is given by :

$H=\dfrac{1}{2}CV^2\\\\H=\dfrac{1}{2}\times 2\times 10^{-6}\times (200)^2\\\\H=0.04\ J$

So, the the heat produced in resistance is 0.04 J.

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Heat produced

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