Question

a capacitor of 20 microfarad and charged to 500v is connected to parallel to another capacitor of 10 microfarad charged to 200v.find the common potential

Answer 1

Ans is 400V
See the soln

Answer 2

Answer:

The common potential is 400 volt.

Explanation:

Given that,

Capacitor $C_{1}=20\times10^{-6}$

Capacitor $C_{2}=10\times10^{-6}$

Charge $V_{1}=500\ v$

Charge$V_{2}=200\ v$

The common potential is

$V= \dfrac{C_{1}V_{1}+C_{2}V_{2}}{C_{1}+C_{2}}$

$V= \dfrac{20\times10^{-6}\times500+10\times10^{-6}\times200}{20\times10^{-6}+10\times10^{-6}}$

$V= 400\ volt$

Hence, The common potential is 400 volt.