Question

a capacitor of 4 microfarad is charged by a battery of 12 volt battery is connected and dielectric slab of dielectric constant between the plates of the capacitor to fill the space complete

Answer 1

Let the dielectric constant be 'k'.

and original capacitance be 'C' = 4 x 10^(-6) F

Thus the new capacitance becomes 'kC'.

Q = CV = 4x10^(-6) x 12

Q = 48 x 10^(-6) C

or Q = 48 microC

if C —> kC

then Q —> kQ = Q' (let)

Q' = 48k microC

Energy,

U = 1/2 CV²

U = 1/2 (4x10^(-6))(12)²

U = 288 x 10^(-6) J

or U = 288 microJ

if C —> kC

then U —> kU = U' (let)

U' = 288k microJ

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