Question

A capacitor of 5nF is given a charge 10mC. What is the amount of work done in moving an electron from the negative plate to the positive plate?

Answer 1

potential difference between two points on equipotential surface equals to zero.

e.g.,  ΔV = 0......(1)

we know, workdone = charge × potential difference

= 10 C × 0v

= 0

hence, workdone to move charge 10c between two points in equipotential surface = 0 J

Answer 2

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Ans

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Potential difference between two points on equipotential surface is equal to zero .

∆V=0

W.k.T

Work done = Charge × Potential energy

=10C×0V

=0

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