Question

A capacitor of a capacitance 3.o micro farred is subjected to a 2000v potential difference across it's terminals calculate the energy stored in the capacitor

Answer 1

Answer:

Potential energy( U)= 1/2 CV² ( where C= capacitance, V= potential )

U= (0.5 × 3× 10⁻⁶ × 2000) J

⇒ U= 3 × 10⁻³ J

Answer 2

Answer:

A capacitor of a capacitance 3 microfarad is subjected to a 2000v potential difference across its terminals. The energy stored in the capacitor will be $6\ J$

Explanation:

• Electric potential energy (E) stored in the capacitor  can be expressed as,

            $E=\frac{1}{2} C V^{2}$    ...(1)

Where C is the capacitance and V is the potential difference between the capacitor plates.

In the question, it is given that,

$V= 2000\ V$

$C =3\ \mu F = 3\times10^{-6} F$

Substitute these  values into equation (1)

$E=\frac{1}{2}\times 3\times10^{-6} \times 2000^{2} = 6\ J$

Thus,

The energy stored in the capacitor   will be $6\ J$