Question

A capacitor of capacitance 0.5 f is connected to a source of alternating e.M.F. Of frequency 100 hz. What is the capacitive reactance? ( = 3.142)

Answer 1

Xc=1/(2*pi*F*c)

c=0.5f , F=100hz

Xc=1/(2*3.14*100*0.5)

=1/(100*3.14)

Xc= 3.18*10^(-3) ohm