Question

A capacitor of capacitance 10µF charged to 100V is connected in series to an uncharged capacitor and the effective potential is 40V. Capacitance of uncharged capacitor is

Answer 1

Answer:

Initial charge on the capacitor Q1 = C1V1

Q1 = 10uF x 100V

Finally this capacitor is connected with another charge less capacitor.

The effective voltage given is 40V.

Since both the capacitors are joined, they should have same potential.

By conservation of charge : sum of the charges after redistribution on two capacitors equals the initial charge on the first capacitor.

Q1 = q1+q2

C1V1 = (C1 + C2)Veffective

10uF x 100V = (10uF + C2) x 40V

25uF = 10uF + C2

C2 = 15uF

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Answer 2

Explanation:

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