Question

) A capacitor of capacitance 10F is charged to 2.5C. Calculate the energy stored in the capacitor.

Answer 1

Answer:

12.5 is the answer as formula of the energy is

U=1/2QC

Answer 2

Answer:

A capacitor of capacitance 10F is charged to 2.5C, then the energy stored in the capacitor is $80J$

Explanation:

• A capacitor is used to store charge

• The electrical potential energy is stored in a capacitor

• For a capacitor with capacitance (C) and potential difference across the battery (V), the energy stored is

        $U=\frac{1}{2}CV^{2}$

• The relation connecting capacitance (C), voltage (V), and the charge stored (q) is $C=qV$

From the question, we have

the capacitance of the capacitor    $C=10F$

the charge stored in the capacitor $q=2.5C$

the voltage across the battery $V=C/q$

⇒$V=10/2.5=4v$

put the values given,

the energy stored in the capacitor is

$U=\frac{1}{2}*10*(4^{2} )$

⇒  $U=80J$