Question

A capacitor of capacitance 50uF is charged with 10V. The energy
of the capacitor is?​

Answer 1

Answer:

E of capacitor

E = CV^2/2

C = 50uF

V= 10V

E= 50 * 10^(-6) * 100 /2

E = 25* 10^(-4) J

hope it helps

Answer 2

The energy  of the capacitor is $\mathbf{2.5\times 10^{-3} \ J}$

Explanation:

• Given data

        Voltage of capacitor (V) = 10 Volt

        Capacitance of capacitor (C) $\mathbf{=50 \ \mu F=50\times 10^{-6} \ F}$

• From formula of energy stored in capacitor

       $\mathbf{Q =\frac{1}{2}CV^{2}}$

       Putting respective value in above equation, we get

      $\mathbf{Q =\frac{1}{2}\times 50\times 10^{-6}\times 10^{2}}$

      On solving, we get

      $\mathbf{Q =2.5\times 10^{-3} \ J}$ = This is energy of capacitor.