Question

a capacitor of capacitance 600PF is charged to a potential 100V by a battery, calculate the stored energy in the capacitor

Answer 1

Energy stored in the capacitor = 0.5CV²
= 0.5 × (600 × 10^-12 Farad) × (100 volt)²
= 3 × 10^-6 joules

∴ 3 × 10^-6 joule of energy is stored in the capacitor.

Answer 2

Answer:

A capacitor of capacitance 600PF is charged to a potential 100V by a battery. The stored energy in the capacitor will be $3\times 10^{-6} J$

Explanation:

• The energy stored in the capacitor depends on the capacitance and voltage between the capacitor plates.

• Let C be the capacitance and V be the potential difference of a capacitor. Then the energy stored (E) in the capacitor is given by the expression,

                     $E = \frac{1}{2}CV^2$   ....(1)

In the question, it is given that,

$C = 600\ PF = 6\times 10^{-10} F$              

$V = 100\ v$

Substitute these values into equation(1),

$E = \frac{1}{2}\times 6\times 10^{-10} \times 100^{2} = 3\times 10^{-6} J$

Amount of energy stored =  $3\times 10^{-6} J$