Question

A capacitor of capacitance C is charged to a
potential difference v through a cell and then
disconnected from it. A charge +Q is now given
to its positive plate. The potential difference
across the capacitor is now
(1) v
(2) V + Q÷C
(3) V+ Q÷2C
(4) V-Q÷c
​

Answer 1

Answer:

option c is the correct answer

Explanation:

Q = CV

V = Q/C

final condition  

charge will redistribute and plates have charge Q + q/2 and -Q – q/2

so now V = (Q + q/2)/C = Q/C + q/2C = V + q/2C

Hope it clears.

Answer 2

Answer:

3

Explanation:

v=q/c

v=(cv+q/2)/c

v=v+q/2c