Question

A capacitor of capacitance C is charges to a potential of V volt. Now the energy stored in the capacitor is E.

If an another identical capacitor is connected in parallel after removing the battery, the energy stored in the

combination is. ​

Answer 1

Explanation:

E = 1/2 CV^2

after removing battery and adding capacitor of capacitance C

effective capacitance = C + C = 2C

new energy E'= 1/2 ×2C V^2 = 2E